13333413250051 has 2 divisors, whose sum is σ = 13333413250052. Its totient is φ = 13333413250050.

The previous prime is 13333413250049. The next prime is 13333413250117. The reversal of 13333413250051 is 15005231433331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13333413250051 - 2¹ = 13333413250049 is a prime.

Together with 13333413250049, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13333413249989 and 13333413250016.

It is not a weakly prime, because it can be changed into another prime (13333413253051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666706625025 + 6666706625026.

It is an arithmetic number, because the mean of its divisors is an integer number (6666706625026).

Almost surely, 2^{13333413250051} is an apocalyptic number.

13333413250051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13333413250051 is an equidigital number, since it uses as much as digits as its factorization.

13333413250051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48600, while the sum is 34.

Adding to 13333413250051 its reverse (15005231433331), we get a palindrome (28338644683382).

The spelling of 13333413250051 in words is "thirteen trillion, three hundred thirty-three billion, four hundred thirteen million, two hundred fifty thousand, fifty-one".