13333422314413 has 2 divisors, whose sum is σ = 13333422314414. Its totient is φ = 13333422314412.

The previous prime is 13333422314411. The next prime is 13333422314447. The reversal of 13333422314413 is 31441322433331.

13333422314413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7369286617449 + 5964135696964 = 2714643^2 + 2442158^2 .

It is a cyclic number.

It is not a de Polignac number, because 13333422314413 - 2¹ = 13333422314411 is a prime.

It is a super-3 number, since 3×13333422314413³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 13333422314411, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13333422314411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666711157206 + 6666711157207.

It is an arithmetic number, because the mean of its divisors is an integer number (6666711157207).

Almost surely, 2^{13333422314413} is an apocalyptic number.

It is an amenable number.

13333422314413 is a deficient number, since it is larger than the sum of its proper divisors (1).

13333422314413 is an equidigital number, since it uses as much as digits as its factorization.

13333422314413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 186624, while the sum is 37.

Adding to 13333422314413 its reverse (31441322433331), we get a palindrome (44774744747744).

The spelling of 13333422314413 in words is "thirteen trillion, three hundred thirty-three billion, four hundred twenty-two million, three hundred fourteen thousand, four hundred thirteen".