Base | Representation |
---|---|
bin | 11000110101110101… |
… | …00110111111110101 |
3 | 1021102102221001110021 |
4 | 30122322212333311 |
5 | 204303114123324 |
6 | 10043210525141 |
7 | 651330104125 |
oct | 143272467765 |
9 | 37372831407 |
10 | 13336473589 |
11 | 5724100aaa |
12 | 27024367b1 |
13 | 13470001ba |
14 | 907314c85 |
15 | 530c67ae4 |
hex | 31aea6ff5 |
13336473589 has 2 divisors, whose sum is σ = 13336473590. Its totient is φ = 13336473588.
The previous prime is 13336473551. The next prime is 13336473641. The reversal of 13336473589 is 98537463331.
It is an a-pointer prime, because the next prime (13336473641) can be obtained adding 13336473589 to its sum of digits (52).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11527672689 + 1808800900 = 107367^2 + 42530^2 .
It is a cyclic number.
It is not a de Polignac number, because 13336473589 - 27 = 13336473461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13336473989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6668236794 + 6668236795.
It is an arithmetic number, because the mean of its divisors is an integer number (6668236795).
Almost surely, 213336473589 is an apocalyptic number.
It is an amenable number.
13336473589 is a deficient number, since it is larger than the sum of its proper divisors (1).
13336473589 is an equidigital number, since it uses as much as digits as its factorization.
13336473589 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4898880, while the sum is 52.
The spelling of 13336473589 in words is "thirteen billion, three hundred thirty-six million, four hundred seventy-three thousand, five hundred eighty-nine".
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