Base | Representation |
---|---|
bin | 111110000111101000… |
… | …1100010111100101101 |
3 | 110202022220002112112021 |
4 | 1330033101202330231 |
5 | 4141200430302023 |
6 | 141141102110141 |
7 | 12431532236131 |
oct | 1741721427455 |
9 | 422286075467 |
10 | 133400244013 |
11 | 51635a61853 |
12 | 21a2b57b351 |
13 | c76c48473a |
14 | 6656cdb3c1 |
15 | 370b61835d |
hex | 1f0f462f2d |
133400244013 has 2 divisors, whose sum is σ = 133400244014. Its totient is φ = 133400244012.
The previous prime is 133400243989. The next prime is 133400244023. The reversal of 133400244013 is 310442004331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101800559844 + 31599684169 = 319062^2 + 177763^2 .
It is a cyclic number.
It is not a de Polignac number, because 133400244013 - 25 = 133400243981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133400244023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66700122006 + 66700122007.
It is an arithmetic number, because the mean of its divisors is an integer number (66700122007).
Almost surely, 2133400244013 is an apocalyptic number.
It is an amenable number.
133400244013 is a deficient number, since it is larger than the sum of its proper divisors (1).
133400244013 is an equidigital number, since it uses as much as digits as its factorization.
133400244013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 133400244013 its reverse (310442004331), we get a palindrome (443842248344).
The spelling of 133400244013 in words is "one hundred thirty-three billion, four hundred million, two hundred forty-four thousand, thirteen".
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