Base | Representation |
---|---|
bin | 11000110110010000… |
… | …11111110110010001 |
3 | 1021102200210000121012 |
4 | 30123020133312101 |
5 | 204310032124241 |
6 | 10043420540305 |
7 | 651403046402 |
oct | 143310376621 |
9 | 37380700535 |
10 | 13340114321 |
11 | 5726168376 |
12 | 27036b1695 |
13 | 13479a6391 |
14 | 9079c19a9 |
15 | 5312366eb |
hex | 31b21fd91 |
13340114321 has 2 divisors, whose sum is σ = 13340114322. Its totient is φ = 13340114320.
The previous prime is 13340114311. The next prime is 13340114323. The reversal of 13340114321 is 12341104331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10498051600 + 2842062721 = 102460^2 + 53311^2 .
It is an emirp because it is prime and its reverse (12341104331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13340114321 is a prime.
Together with 13340114323, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13340114323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670057160 + 6670057161.
It is an arithmetic number, because the mean of its divisors is an integer number (6670057161).
Almost surely, 213340114321 is an apocalyptic number.
It is an amenable number.
13340114321 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340114321 is an equidigital number, since it uses as much as digits as its factorization.
13340114321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 13340114321 its reverse (12341104331), we get a palindrome (25681218652).
The spelling of 13340114321 in words is "thirteen billion, three hundred forty million, one hundred fourteen thousand, three hundred twenty-one".
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