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13340114323 is a prime number
BaseRepresentation
bin11000110110010000…
…11111110110010011
31021102200210000121021
430123020133312103
5204310032124243
610043420540311
7651403046404
oct143310376623
937380700537
1013340114323
115726168378
1227036b1697
1313479a6393
149079c19ab
155312366ed
hex31b21fd93

13340114323 has 2 divisors, whose sum is σ = 13340114324. Its totient is φ = 13340114322.

The previous prime is 13340114321. The next prime is 13340114329. The reversal of 13340114323 is 32341104331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13340114323 - 21 = 13340114321 is a prime.

It is a super-3 number, since 3×133401143233 (a number of 31 digits) contains 333 as substring.

Together with 13340114321, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13340114321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670057161 + 6670057162.

It is an arithmetic number, because the mean of its divisors is an integer number (6670057162).

Almost surely, 213340114323 is an apocalyptic number.

13340114323 is a deficient number, since it is larger than the sum of its proper divisors (1).

13340114323 is an equidigital number, since it uses as much as digits as its factorization.

13340114323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13340114323 its reverse (32341104331), we get a palindrome (45681218654).

The spelling of 13340114323 in words is "thirteen billion, three hundred forty million, one hundred fourteen thousand, three hundred twenty-three".