Base | Representation |
---|---|
bin | 1100001000011111110100… |
… | …1100101000101111001010 |
3 | 1202020022011222220222012002 |
4 | 3002013331030220233022 |
5 | 3222031032034333224 |
6 | 44212211150351002 |
7 | 2544535433666330 |
oct | 302077514505712 |
9 | 52208158828162 |
10 | 13340121402314 |
11 | 4283571834423 |
12 | 15b54a37bb462 |
13 | 759c77a64865 |
14 | 3419458d7b50 |
15 | 18201930d9ae |
hex | c21fd328bca |
13340121402314 has 64 divisors (see below), whose sum is σ = 23532590914560. Its totient is φ = 5553111874560.
The previous prime is 13340121402313. The next prime is 13340121402317. The reversal of 13340121402314 is 41320412104331.
13340121402314 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not an unprimeable number, because it can be changed into a prime (13340121402313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 344428502 + ... + 344467230.
It is an arithmetic number, because the mean of its divisors is an integer number (367696733040).
Almost surely, 213340121402314 is an apocalyptic number.
13340121402314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13340121402314 is a deficient number, since it is larger than the sum of its proper divisors (10192469512246).
13340121402314 is a wasteful number, since it uses less digits than its factorization.
13340121402314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42743.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 13340121402314 its reverse (41320412104331), we get a palindrome (54660533506645).
The spelling of 13340121402314 in words is "thirteen trillion, three hundred forty billion, one hundred twenty-one million, four hundred two thousand, three hundred fourteen".
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