Base | Representation |
---|---|
bin | 111110000111101100… |
… | …0101000000110000100 |
3 | 110202100000120211121020 |
4 | 1330033120220012010 |
5 | 4141201414200400 |
6 | 141141205551140 |
7 | 12431554066353 |
oct | 1741730500604 |
9 | 422300524536 |
10 | 133402100100 |
11 | 5163700a305 |
12 | 21a301154b0 |
13 | c76c984509 |
14 | 665726199a |
15 | 370b8832a0 |
hex | 1f0f628184 |
133402100100 has 36 divisors (see below), whose sum is σ = 385976743824. Its totient is φ = 35573893280.
The previous prime is 133402100087. The next prime is 133402100101. The reversal of 133402100100 is 1001204331.
It is a super-2 number, since 2×1334021001002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 133402100100.
It is not an unprimeable number, because it can be changed into a prime (133402100101) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 222336534 + ... + 222337133.
Almost surely, 2133402100100 is an apocalyptic number.
133402100100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133402100100 is an abundant number, since it is smaller than the sum of its proper divisors (252574643724).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133402100100 is a wasteful number, since it uses less digits than its factorization.
133402100100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 444673684 (or 444673677 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 133402100100 its reverse (1001204331), we get a palindrome (134403304431).
The spelling of 133402100100 in words is "one hundred thirty-three billion, four hundred two million, one hundred thousand, one hundred".
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