Base | Representation |
---|---|
bin | 11000110110010001… |
… | …11000010000110001 |
3 | 1021102200222002202220 |
4 | 30123020320100301 |
5 | 204310043324241 |
6 | 10043423031253 |
7 | 651403644060 |
oct | 143310702061 |
9 | 37380862686 |
10 | 13340214321 |
11 | 5726226515 |
12 | 270373b529 |
13 | 1347a0ca55 |
14 | 907a0a1d7 |
15 | 531256166 |
hex | 31b238431 |
13340214321 has 64 divisors (see below), whose sum is σ = 21792830976. Its totient is φ = 7098624000.
The previous prime is 13340214311. The next prime is 13340214413. The reversal of 13340214321 is 12341204331.
It is a happy number.
It is not a de Polignac number, because 13340214321 - 213 = 13340206129 is a prime.
It is a super-2 number, since 2×133402143212 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13340214291 and 13340214300.
It is not an unprimeable number, because it can be changed into a prime (13340214311) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1684471 + ... + 1692371.
It is an arithmetic number, because the mean of its divisors is an integer number (340512984).
Almost surely, 213340214321 is an apocalyptic number.
It is an amenable number.
13340214321 is a deficient number, since it is larger than the sum of its proper divisors (8452616655).
13340214321 is a wasteful number, since it uses less digits than its factorization.
13340214321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8042.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 13340214321 its reverse (12341204331), we get a palindrome (25681418652).
The spelling of 13340214321 in words is "thirteen billion, three hundred forty million, two hundred fourteen thousand, three hundred twenty-one".
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