1334025613 has 2 divisors, whose sum is σ = 1334025614. Its totient is φ = 1334025612.

The previous prime is 1334025571. The next prime is 1334025631. The reversal of 1334025613 is 3165204331.

Together with next prime (1334025631) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1301910724 + 32114889 = 36082^2 + 5667^2 .

It is a cyclic number.

It is not a de Polignac number, because 1334025613 - 2⁹ = 1334025101 is a prime.

It is a super-3 number, since 3×1334025613³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1334035613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667012806 + 667012807.

It is an arithmetic number, because the mean of its divisors is an integer number (667012807).

Almost surely, 2^1334025613 is an apocalyptic number.

It is an amenable number.

1334025613 is a deficient number, since it is larger than the sum of its proper divisors (1).

1334025613 is an equidigital number, since it uses as much as digits as its factorization.

1334025613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 28.

The square root of 1334025613 is about 36524.3153666157. The cubic root of 1334025613 is about 1100.8328714312.

Adding to 1334025613 its reverse (3165204331), we get a palindrome (4499229944).

The spelling of 1334025613 in words is "one billion, three hundred thirty-four million, twenty-five thousand, six hundred thirteen".