Base | Representation |
---|---|
bin | 10011011010011011000… |
… | …111010000000100111011 |
3 | 11201112101200210222020012 |
4 | 103122123013100010323 |
5 | 133324104302343344 |
6 | 2500503414452135 |
7 | 165244544603504 |
oct | 23323307200473 |
9 | 4645350728205 |
10 | 1334042231099 |
11 | 474845074286 |
12 | 19666806404b |
13 | 98a51a79156 |
14 | 487d47bbbab |
15 | 24a7c86729e |
hex | 1369b1d013b |
1334042231099 has 2 divisors, whose sum is σ = 1334042231100. Its totient is φ = 1334042231098.
The previous prime is 1334042231083. The next prime is 1334042231101. The reversal of 1334042231099 is 9901322404331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1334042231099 - 24 = 1334042231083 is a prime.
Together with 1334042231101, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1334042231009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667021115549 + 667021115550.
It is an arithmetic number, because the mean of its divisors is an integer number (667021115550).
Almost surely, 21334042231099 is an apocalyptic number.
1334042231099 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334042231099 is an equidigital number, since it uses as much as digits as its factorization.
1334042231099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 139968, while the sum is 41.
The spelling of 1334042231099 in words is "one trillion, three hundred thirty-four billion, forty-two million, two hundred thirty-one thousand, ninety-nine".
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