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1334042231101 is a prime number
BaseRepresentation
bin10011011010011011000…
…111010000000100111101
311201112101200210222020021
4103122123013100010331
5133324104302343401
62500503414452141
7165244544603506
oct23323307200475
94645350728207
101334042231101
11474845074288
12196668064051
1398a51a79158
14487d47bbbad
1524a7c8672a1
hex1369b1d013d

1334042231101 has 2 divisors, whose sum is σ = 1334042231102. Its totient is φ = 1334042231100.

The previous prime is 1334042231099. The next prime is 1334042231117. The reversal of 1334042231101 is 1011322404331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 694480556025 + 639561675076 = 833355^2 + 799726^2 .

It is an emirp because it is prime and its reverse (1011322404331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1334042231101 - 21 = 1334042231099 is a prime.

Together with 1334042231099, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1334042231131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667021115550 + 667021115551.

It is an arithmetic number, because the mean of its divisors is an integer number (667021115551).

Almost surely, 21334042231101 is an apocalyptic number.

It is an amenable number.

1334042231101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1334042231101 is an equidigital number, since it uses as much as digits as its factorization.

1334042231101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1334042231101 its reverse (1011322404331), we get a palindrome (2345364635432).

The spelling of 1334042231101 in words is "one trillion, three hundred thirty-four billion, forty-two million, two hundred thirty-one thousand, one hundred one".