13341102430421 has 2 divisors, whose sum is σ = 13341102430422. Its totient is φ = 13341102430420.

The previous prime is 13341102430363. The next prime is 13341102430423. The reversal of 13341102430421 is 12403420114331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13062333214225 + 278769216196 = 3614185^2 + 527986^2 .

It is a cyclic number.

It is not a de Polignac number, because 13341102430421 - 2²² = 13341098236117 is a prime.

It is a super-2 number, since 2×13341102430421² (a number of 27 digits) contains 22 as substring.

Together with 13341102430423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13341102430423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670551215210 + 6670551215211.

It is an arithmetic number, because the mean of its divisors is an integer number (6670551215211).

Almost surely, 2^{13341102430421} is an apocalyptic number.

It is an amenable number.

13341102430421 is a deficient number, since it is larger than the sum of its proper divisors (1).

13341102430421 is an equidigital number, since it uses as much as digits as its factorization.

13341102430421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13341102430421 its reverse (12403420114331), we get a palindrome (25744522544752).

The spelling of 13341102430421 in words is "thirteen trillion, three hundred forty-one billion, one hundred two million, four hundred thirty thousand, four hundred twenty-one".