Base | Representation |
---|---|
bin | 1100001000100011100111… |
… | …1110111110110010111111 |
3 | 1202020101211001220201122201 |
4 | 3002020321332332302333 |
5 | 3222040124123422311 |
6 | 44212500301052331 |
7 | 2544602626262206 |
oct | 302107176766277 |
9 | 52211731821581 |
10 | 13341141232831 |
11 | 4283a45472165 |
12 | 15b57292570a7 |
13 | 75a0ab125c79 |
14 | 341a0112823d |
15 | 182078b0a9c1 |
hex | c2239fbecbf |
13341141232831 has 2 divisors, whose sum is σ = 13341141232832. Its totient is φ = 13341141232830.
The previous prime is 13341141232829. The next prime is 13341141232889. The reversal of 13341141232831 is 13823214114331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13341141232831 - 21 = 13341141232829 is a prime.
It is a super-2 number, since 2×133411412328312 (a number of 27 digits) contains 22 as substring.
Together with 13341141232829, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13341141235831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670570616415 + 6670570616416.
It is an arithmetic number, because the mean of its divisors is an integer number (6670570616416).
Almost surely, 213341141232831 is an apocalyptic number.
13341141232831 is a deficient number, since it is larger than the sum of its proper divisors (1).
13341141232831 is an equidigital number, since it uses as much as digits as its factorization.
13341141232831 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 41472, while the sum is 37.
The spelling of 13341141232831 in words is "thirteen trillion, three hundred forty-one billion, one hundred forty-one million, two hundred thirty-two thousand, eight hundred thirty-one".
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