Base | Representation |
---|---|
bin | 111110000111111111… |
… | …1001100011010100101 |
3 | 110202100201121111020121 |
4 | 1330033333030122211 |
5 | 4141212011212331 |
6 | 141142210401541 |
7 | 12432036035314 |
oct | 1741777143245 |
9 | 422321544217 |
10 | 133412210341 |
11 | 51641795283 |
12 | 21a335902b1 |
13 | c771ab42c7 |
14 | 665873427b |
15 | 370c6cdc11 |
hex | 1f0ffcc6a5 |
133412210341 has 2 divisors, whose sum is σ = 133412210342. Its totient is φ = 133412210340.
The previous prime is 133412210317. The next prime is 133412210381. The reversal of 133412210341 is 143012214331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 109279830625 + 24132379716 = 330575^2 + 155346^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133412210341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133412210381) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66706105170 + 66706105171.
It is an arithmetic number, because the mean of its divisors is an integer number (66706105171).
Almost surely, 2133412210341 is an apocalyptic number.
It is an amenable number.
133412210341 is a deficient number, since it is larger than the sum of its proper divisors (1).
133412210341 is an equidigital number, since it uses as much as digits as its factorization.
133412210341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 133412210341 its reverse (143012214331), we get a palindrome (276424424672).
The spelling of 133412210341 in words is "one hundred thirty-three billion, four hundred twelve million, two hundred ten thousand, three hundred forty-one".
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