Base | Representation |
---|---|
bin | 1100001000100100101000… |
… | …1000011000010010001011 |
3 | 1202020102111221122211102111 |
4 | 3002021022020120102023 |
5 | 3222041203001210404 |
6 | 44212543215243151 |
7 | 2544612426006511 |
oct | 302111210302213 |
9 | 52212457584374 |
10 | 13341412131979 |
11 | 428407437a758 |
12 | 15b57a3b194b7 |
13 | 75a1222a5119 |
14 | 341a290c44b1 |
15 | 1820927bc104 |
hex | c224a21848b |
13341412131979 has 2 divisors, whose sum is σ = 13341412131980. Its totient is φ = 13341412131978.
The previous prime is 13341412131977. The next prime is 13341412132091. The reversal of 13341412131979 is 97913121414331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13341412131979 - 21 = 13341412131977 is a prime.
It is a super-2 number, since 2×133414121319792 (a number of 27 digits) contains 22 as substring.
Together with 13341412131977, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13341412131977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670706065989 + 6670706065990.
It is an arithmetic number, because the mean of its divisors is an integer number (6670706065990).
Almost surely, 213341412131979 is an apocalyptic number.
13341412131979 is a deficient number, since it is larger than the sum of its proper divisors (1).
13341412131979 is an equidigital number, since it uses as much as digits as its factorization.
13341412131979 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 489888, while the sum is 49.
The spelling of 13341412131979 in words is "thirteen trillion, three hundred forty-one billion, four hundred twelve million, one hundred thirty-one thousand, nine hundred seventy-nine".
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