13341412131977 has 2 divisors, whose sum is σ = 13341412131978. Its totient is φ = 13341412131976.

The previous prime is 13341412131947. The next prime is 13341412131979. The reversal of 13341412131977 is 77913121414331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11217569341696 + 2123842790281 = 3349264^2 + 1457341^2 .

It is a cyclic number.

It is not a de Polignac number, because 13341412131977 - 2⁸ = 13341412131721 is a prime.

Together with 13341412131979, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13341412131979) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670706065988 + 6670706065989.

It is an arithmetic number, because the mean of its divisors is an integer number (6670706065989).

Almost surely, 2^{13341412131977} is an apocalyptic number.

It is an amenable number.

13341412131977 is a deficient number, since it is larger than the sum of its proper divisors (1).

13341412131977 is an equidigital number, since it uses as much as digits as its factorization.

13341412131977 is an evil number, because the sum of its binary digits is even.

The product of its digits is 381024, while the sum is 47.

The spelling of 13341412131977 in words is "thirteen trillion, three hundred forty-one billion, four hundred twelve million, one hundred thirty-one thousand, nine hundred seventy-seven".