133420404121 has 2 divisors, whose sum is σ = 133420404122. Its totient is φ = 133420404120.

The previous prime is 133420404119. The next prime is 133420404149. The reversal of 133420404121 is 121404024331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107148856896 + 26271547225 = 327336^2 + 162085^2 .

It is a cyclic number.

It is not a de Polignac number, because 133420404121 - 2¹ = 133420404119 is a prime.

Together with 133420404119, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (133420404421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66710202060 + 66710202061.

It is an arithmetic number, because the mean of its divisors is an integer number (66710202061).

Almost surely, 2^133420404121 is an apocalyptic number.

It is an amenable number.

133420404121 is a deficient number, since it is larger than the sum of its proper divisors (1).

133420404121 is an equidigital number, since it uses as much as digits as its factorization.

133420404121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 133420404121 its reverse (121404024331), we get a palindrome (254824428452).

The spelling of 133420404121 in words is "one hundred thirty-three billion, four hundred twenty million, four hundred four thousand, one hundred twenty-one".