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13342110231340 = 22511374014087481
BaseRepresentation
bin1100001000100111001110…
…1111011010101100101100
31202020111022121020221201101
43002021303233122230230
53222044120204400330
644213140354052444
72544635633523562
oct302116357325454
952214277227641
1013342110231340
1142843a2441080
1215b595987a124
1375a203aca377
14341a93ac5a32
151820d3c164ca
hexc2273bdab2c

13342110231340 has 96 divisors (see below), whose sum is σ = 31469949016128. Its totient is φ = 4708776960000.

The previous prime is 13342110231311. The next prime is 13342110231431. The reversal of 13342110231340 is 4313201124331.

It is a junction number, because it is equal to n+sod(n) for n = 13342110231299 and 13342110231308.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1220400 + ... + 5307880.

It is an arithmetic number, because the mean of its divisors is an integer number (327811968918).

Almost surely, 213342110231340 is an apocalyptic number.

13342110231340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13342110231340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15734974508064).

13342110231340 is an abundant number, since it is smaller than the sum of its proper divisors (18127838784788).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13342110231340 is a wasteful number, since it uses less digits than its factorization.

13342110231340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4087939 (or 4087937 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13342110231340 its reverse (4313201124331), we get a palindrome (17655311355671).

The spelling of 13342110231340 in words is "thirteen trillion, three hundred forty-two billion, one hundred ten million, two hundred thirty-one thousand, three hundred forty".

Divisors: 1 2 4 5 10 11 20 22 37 44 55 74 110 148 185 220 370 401 407 740 802 814 1604 1628 2005 2035 4010 4070 4411 8020 8140 8822 14837 17644 22055 29674 44110 59348 74185 88220 148370 163207 296740 326414 652828 816035 1632070 3264140 4087481 8174962 16349924 20437405 40874810 44962291 81749620 89924582 151236797 179849164 224811455 302473594 449622910 604947188 756183985 899245820 1512367970 1639079881 1663604767 3024735940 3278159762 3327209534 6556319524 6654419068 8195399405 8318023835 16390798810 16636047670 18029878691 32781597620 33272095340 36059757382 60645955597 72119514764 90149393455 121291911194 180298786910 242583822388 303229777985 360597573820 606459555970 667105511567 1212919111940 1334211023134 2668422046268 3335527557835 6671055115670 13342110231340