Base | Representation |
---|---|
bin | 11000110110100111… |
… | …11011110001000001 |
3 | 1021102220102022222212 |
4 | 30123103323301001 |
5 | 204311314043012 |
6 | 10044005111505 |
7 | 651440403626 |
oct | 143323736101 |
9 | 37386368885 |
10 | 13343112257 |
11 | 5727925802 |
12 | 27046b8595 |
13 | 13484b5ac7 |
14 | 90816234d |
15 | 531629b22 |
hex | 31b4fbc41 |
13343112257 has 2 divisors, whose sum is σ = 13343112258. Its totient is φ = 13343112256.
The previous prime is 13343112173. The next prime is 13343112259. The reversal of 13343112257 is 75221134331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6910430641 + 6432681616 = 83129^2 + 80204^2 .
It is a cyclic number.
It is not a de Polignac number, because 13343112257 - 222 = 13338917953 is a prime.
Together with 13343112259, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13343112259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671556128 + 6671556129.
It is an arithmetic number, because the mean of its divisors is an integer number (6671556129).
Almost surely, 213343112257 is an apocalyptic number.
It is an amenable number.
13343112257 is a deficient number, since it is larger than the sum of its proper divisors (1).
13343112257 is an equidigital number, since it uses as much as digits as its factorization.
13343112257 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15120, while the sum is 32.
Adding to 13343112257 its reverse (75221134331), we get a palindrome (88564246588).
The spelling of 13343112257 in words is "thirteen billion, three hundred forty-three million, one hundred twelve thousand, two hundred fifty-seven".
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