Base | Representation |
---|---|
bin | 1100001000101011000000… |
… | …1011000110010110101111 |
3 | 1202020120221021001212212112 |
4 | 3002022300023012112233 |
5 | 3222103204233333012 |
6 | 44213425133154235 |
7 | 2545003024454252 |
oct | 302126013062657 |
9 | 52216837055775 |
10 | 13343124121007 |
11 | 428487279141a |
12 | 15b5ba132b97b |
13 | 75a335b8b695 |
14 | 341b4c60b099 |
15 | 182142c3d122 |
hex | c22b02c65af |
13343124121007 has 2 divisors, whose sum is σ = 13343124121008. Its totient is φ = 13343124121006.
The previous prime is 13343124120979. The next prime is 13343124121081. The reversal of 13343124121007 is 70012142134331.
It is a weak prime.
It is an emirp because it is prime and its reverse (70012142134331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13343124121007 - 220 = 13343123072431 is a prime.
It is a super-2 number, since 2×133431241210072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13343124121087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671562060503 + 6671562060504.
It is an arithmetic number, because the mean of its divisors is an integer number (6671562060504).
Almost surely, 213343124121007 is an apocalyptic number.
13343124121007 is a deficient number, since it is larger than the sum of its proper divisors (1).
13343124121007 is an equidigital number, since it uses as much as digits as its factorization.
13343124121007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 13343124121007 its reverse (70012142134331), we get a palindrome (83355266255338).
The spelling of 13343124121007 in words is "thirteen trillion, three hundred forty-three billion, one hundred twenty-four million, one hundred twenty-one thousand, seven".
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