Base | Representation |
---|---|
bin | 1100001000101011000000… |
… | …1011000110010110110110 |
3 | 1202020120221021001212212210 |
4 | 3002022300023012112312 |
5 | 3222103204233333024 |
6 | 44213425133154250 |
7 | 2545003024454262 |
oct | 302126013062666 |
9 | 52216837055783 |
10 | 13343124121014 |
11 | 4284872791426 |
12 | 15b5ba132b986 |
13 | 75a335b8b69c |
14 | 341b4c60b0a2 |
15 | 182142c3d129 |
hex | c22b02c65b6 |
13343124121014 has 16 divisors (see below), whose sum is σ = 26686432926720. Its totient is φ = 4447677259560.
The previous prime is 13343124121007. The next prime is 13343124121081. The reversal of 13343124121014 is 41012142134331.
It is a super-2 number, since 2×133431241210142 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6746982 + ... + 8497529.
It is an arithmetic number, because the mean of its divisors is an integer number (1667902057920).
Almost surely, 213343124121014 is an apocalyptic number.
13343124121014 is an abundant number, since it is smaller than the sum of its proper divisors (13343308805706).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13343124121014 is a wasteful number, since it uses less digits than its factorization.
13343124121014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15390395.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 13343124121014 its reverse (41012142134331), we get a palindrome (54355266255345).
The spelling of 13343124121014 in words is "thirteen trillion, three hundred forty-three billion, one hundred twenty-four million, one hundred twenty-one thousand, fourteen".
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