Base | Representation |
---|---|
bin | 10011011010101100010… |
… | …101101111011010011101 |
3 | 11201120010211122020211212 |
4 | 103122230111233122131 |
5 | 133330202244222031 |
6 | 2500552221154205 |
7 | 165254654264342 |
oct | 23325425573235 |
9 | 4646124566755 |
10 | 1334331242141 |
11 | 474983222587 |
12 | 1967289bb965 |
13 | 98a998ca1c1 |
14 | 48820d307c9 |
15 | 24a97e0512b |
hex | 136ac56f69d |
1334331242141 has 2 divisors, whose sum is σ = 1334331242142. Its totient is φ = 1334331242140.
The previous prime is 1334331242131. The next prime is 1334331242149. The reversal of 1334331242141 is 1412421334331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1152249818041 + 182081424100 = 1073429^2 + 426710^2 .
It is a cyclic number.
It is not a de Polignac number, because 1334331242141 - 214 = 1334331225757 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1334331242098 and 1334331242107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1334331242149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667165621070 + 667165621071.
It is an arithmetic number, because the mean of its divisors is an integer number (667165621071).
Almost surely, 21334331242141 is an apocalyptic number.
It is an amenable number.
1334331242141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334331242141 is an equidigital number, since it uses as much as digits as its factorization.
1334331242141 is an evil number, because the sum of its binary digits is even.
The product of its digits is 20736, while the sum is 32.
Adding to 1334331242141 its reverse (1412421334331), we get a palindrome (2746752576472).
The spelling of 1334331242141 in words is "one trillion, three hundred thirty-four billion, three hundred thirty-one million, two hundred forty-two thousand, one hundred forty-one".
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