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1334331242417 is a prime number
BaseRepresentation
bin10011011010101100010…
…101101111011110110001
311201120010211122021020002
4103122230111233132301
5133330202244224132
62500552221155345
7165254654265215
oct23325425573661
94646124567202
101334331242417
11474983222808
121967289bbb55
1398a998ca374
1448820d30945
1524a97e05262
hex136ac56f7b1

1334331242417 has 2 divisors, whose sum is σ = 1334331242418. Its totient is φ = 1334331242416.

The previous prime is 1334331242357. The next prime is 1334331242441. The reversal of 1334331242417 is 7142421334331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1311118891681 + 23212350736 = 1145041^2 + 152356^2 .

It is a cyclic number.

It is not a de Polignac number, because 1334331242417 - 212 = 1334331238321 is a prime.

It is a super-4 number, since 4×13343312424174 (a number of 50 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (1334331242617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667165621208 + 667165621209.

It is an arithmetic number, because the mean of its divisors is an integer number (667165621209).

Almost surely, 21334331242417 is an apocalyptic number.

It is an amenable number.

1334331242417 is a deficient number, since it is larger than the sum of its proper divisors (1).

1334331242417 is an equidigital number, since it uses as much as digits as its factorization.

1334331242417 is an evil number, because the sum of its binary digits is even.

The product of its digits is 145152, while the sum is 38.

Adding to 1334331242417 its reverse (7142421334331), we get a palindrome (8476752576748).

The spelling of 1334331242417 in words is "one trillion, three hundred thirty-four billion, three hundred thirty-one million, two hundred forty-two thousand, four hundred seventeen".