Base | Representation |
---|---|
bin | 111110001000101000… |
… | …0000010001010100111 |
3 | 110202102012111010202201 |
4 | 1330101100002022213 |
5 | 4141232422331043 |
6 | 141144244515331 |
7 | 12432414126535 |
oct | 1742120021247 |
9 | 422365433681 |
10 | 133433402023 |
11 | 51652749969 |
12 | 21a3a6abb47 |
13 | c7762c3c6c |
14 | 665b48d155 |
15 | 370e4b7c4d |
hex | 1f114022a7 |
133433402023 has 2 divisors, whose sum is σ = 133433402024. Its totient is φ = 133433402022.
The previous prime is 133433401963. The next prime is 133433402041. The reversal of 133433402023 is 320204334331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133433402023 - 29 = 133433401511 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133433401982 and 133433402000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133433406023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66716701011 + 66716701012.
It is an arithmetic number, because the mean of its divisors is an integer number (66716701012).
Almost surely, 2133433402023 is an apocalyptic number.
133433402023 is a deficient number, since it is larger than the sum of its proper divisors (1).
133433402023 is an equidigital number, since it uses as much as digits as its factorization.
133433402023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 28.
Adding to 133433402023 its reverse (320204334331), we get a palindrome (453637736354).
The spelling of 133433402023 in words is "one hundred thirty-three billion, four hundred thirty-three million, four hundred two thousand, twenty-three".
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