133434011230 has 16 divisors (see below), whose sum is σ = 258656698944. Its totient is φ = 49267942560.

The previous prime is 133434011219. The next prime is 133434011237. The reversal of 133434011230 is 32110434331.

It is a super-2 number, since 2×133434011230² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133434011195 and 133434011204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133434011237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 513207606 + ... + 513207865.

It is an arithmetic number, because the mean of its divisors is an integer number (16166043684).

Almost surely, 2^133434011230 is an apocalyptic number.

133434011230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

133434011230 is a deficient number, since it is larger than the sum of its proper divisors (125222687714).

133434011230 is a wasteful number, since it uses less digits than its factorization.

133434011230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1026415491.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 133434011230 its reverse (32110434331), we get a palindrome (165544445561).

The spelling of 133434011230 in words is "one hundred thirty-three billion, four hundred thirty-four million, eleven thousand, two hundred thirty".