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133434411523397 is a prime number
BaseRepresentation
bin11110010101101110011110…
…101100110001110101000101
3122111110012112120012110000022
4132111232132230301311011
5114442142133322222042
61151442531124024525
740051214052036635
oct3625563654616505
9574405476173008
10133434411523397
113957524174a136
1212b70596532145
13595ba70a5458a
1424d438d53a6c5
151065e06772cd2
hex795b9eb31d45

133434411523397 has 2 divisors, whose sum is σ = 133434411523398. Its totient is φ = 133434411523396.

The previous prime is 133434411523351. The next prime is 133434411523433. The reversal of 133434411523397 is 793325114434331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102736894518241 + 30697517005156 = 10135921^2 + 5540534^2 .

It is an emirp because it is prime and its reverse (793325114434331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133434411523397 - 212 = 133434411519301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133434411523697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66717205761698 + 66717205761699.

It is an arithmetic number, because the mean of its divisors is an integer number (66717205761699).

Almost surely, 2133434411523397 is an apocalyptic number.

It is an amenable number.

133434411523397 is a deficient number, since it is larger than the sum of its proper divisors (1).

133434411523397 is an equidigital number, since it uses as much as digits as its factorization.

133434411523397 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9797760, while the sum is 53.

The spelling of 133434411523397 in words is "one hundred thirty-three trillion, four hundred thirty-four billion, four hundred eleven million, five hundred twenty-three thousand, three hundred ninety-seven".