Search a number
-
+
133458012007 is a prime number
BaseRepresentation
bin111110001001010110…
…1111010011101100111
3110202110220210110022121
41330102231322131213
54141310222341012
6141150524210411
712433133246005
oct1742255723547
9422426713277
10133458012007
11516656287a1
1221a46999a07
13c77b42c798
146660857a75
153711729a07
hex1f12b7a767

133458012007 has 2 divisors, whose sum is σ = 133458012008. Its totient is φ = 133458012006.

The previous prime is 133458011993. The next prime is 133458012011. The reversal of 133458012007 is 700210854331.

It is a strong prime.

It is an emirp because it is prime and its reverse (700210854331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133458012007 is a prime.

It is a super-2 number, since 2×1334580120072 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133458012307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66729006003 + 66729006004.

It is an arithmetic number, because the mean of its divisors is an integer number (66729006004).

Almost surely, 2133458012007 is an apocalyptic number.

133458012007 is a deficient number, since it is larger than the sum of its proper divisors (1).

133458012007 is an equidigital number, since it uses as much as digits as its factorization.

133458012007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 34.

Adding to 133458012007 its reverse (700210854331), we get a palindrome (833668866338).

The spelling of 133458012007 in words is "one hundred thirty-three billion, four hundred fifty-eight million, twelve thousand, seven".