133462400634149 has 2 divisors, whose sum is σ = 133462400634150. Its totient is φ = 133462400634148.

The previous prime is 133462400634133. The next prime is 133462400634151. The reversal of 133462400634149 is 941436004264331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96573565024225 + 36888835609924 = 9827185^2 + 6073618^2 .

It is an emirp because it is prime and its reverse (941436004264331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133462400634149 - 2⁴ = 133462400634133 is a prime.

It is a super-3 number, since 3×133462400634149³ (a number of 43 digits) contains 333 as substring.

Together with 133462400634151, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 133462400634097 and 133462400634106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133462400634109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66731200317074 + 66731200317075.

It is an arithmetic number, because the mean of its divisors is an integer number (66731200317075).

Almost surely, 2^{133462400634149} is an apocalyptic number.

It is an amenable number.

133462400634149 is a deficient number, since it is larger than the sum of its proper divisors (1).

133462400634149 is an equidigital number, since it uses as much as digits as its factorization.

133462400634149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4478976, while the sum is 50.

The spelling of 133462400634149 in words is "one hundred thirty-three trillion, four hundred sixty-two billion, four hundred million, six hundred thirty-four thousand, one hundred forty-nine".