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133473473468141 is a prime number
BaseRepresentation
bin11110010110010010110110…
…111110010001011011101101
3122111120221100212010211121112
4132112102312332101123231
5114443312133201440031
61151512511153041405
740054066046063522
oct3626226676213355
9574527325124545
10133473473468141
113958a8671433a4
1212b78078256265
135962657677b51
1424d62172c3149
151066e40c1262b
hex7964b6f916ed

133473473468141 has 2 divisors, whose sum is σ = 133473473468142. Its totient is φ = 133473473468140.

The previous prime is 133473473468119. The next prime is 133473473468183. The reversal of 133473473468141 is 141864374374331.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69674579236900 + 63798894231241 = 8347130^2 + 7987421^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133473473468141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133473473168141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66736736734070 + 66736736734071.

It is an arithmetic number, because the mean of its divisors is an integer number (66736736734071).

Almost surely, 2133473473468141 is an apocalyptic number.

It is an amenable number.

133473473468141 is a deficient number, since it is larger than the sum of its proper divisors (1).

133473473468141 is an equidigital number, since it uses as much as digits as its factorization.

133473473468141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48771072, while the sum is 59.

The spelling of 133473473468141 in words is "one hundred thirty-three trillion, four hundred seventy-three billion, four hundred seventy-three million, four hundred sixty-eight thousand, one hundred forty-one".