133479947 has 2 divisors, whose sum is σ = 133479948. Its totient is φ = 133479946.

The previous prime is 133479919. The next prime is 133479949. The reversal of 133479947 is 749974331.

It is a strong prime.

It is an emirp because it is prime and its reverse (749974331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133479947 - 2¹² = 133475851 is a prime.

It is a super-3 number, since 3×133479947³ (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 133479949, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133479949) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66739973 + 66739974.

It is an arithmetic number, because the mean of its divisors is an integer number (66739974).

Almost surely, 2^133479947 is an apocalyptic number.

133479947 is a deficient number, since it is larger than the sum of its proper divisors (1).

133479947 is an equidigital number, since it uses as much as digits as its factorization.

133479947 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 571536, while the sum is 47.

The square root of 133479947 is about 11553.3521975226. The cubic root of 133479947 is about 511.0601387293.

The spelling of 133479947 in words is "one hundred thirty-three million, four hundred seventy-nine thousand, nine hundred forty-seven".