Base | Representation |
---|---|
bin | 11000110111010111… |
… | …11000010000011111 |
3 | 1021110100020020112112 |
4 | 30123223320100133 |
5 | 204314420424333 |
6 | 10044351424235 |
7 | 651544636313 |
oct | 143353702037 |
9 | 37410206475 |
10 | 13349389343 |
11 | 5730422884 |
12 | 270682507b |
13 | 13498a2c64 |
14 | 908d17b43 |
15 | 531e69948 |
hex | 31baf841f |
13349389343 has 2 divisors, whose sum is σ = 13349389344. Its totient is φ = 13349389342.
The previous prime is 13349389327. The next prime is 13349389393. The reversal of 13349389343 is 34398394331.
It is an a-pointer prime, because the next prime (13349389393) can be obtained adding 13349389343 to its sum of digits (50).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13349389343 - 24 = 13349389327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13349389291 and 13349389300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13349389393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6674694671 + 6674694672.
It is an arithmetic number, because the mean of its divisors is an integer number (6674694672).
Almost surely, 213349389343 is an apocalyptic number.
13349389343 is a deficient number, since it is larger than the sum of its proper divisors (1).
13349389343 is an equidigital number, since it uses as much as digits as its factorization.
13349389343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2519424, while the sum is 50.
The spelling of 13349389343 in words is "thirteen billion, three hundred forty-nine million, three hundred eighty-nine thousand, three hundred forty-three".
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