Base | Representation |
---|---|
bin | 1100001001001010010101… |
… | …0110100011101110110110 |
3 | 1202021101122020221022100001 |
4 | 3002102211112203232312 |
5 | 3222222414310311014 |
6 | 44221335342141514 |
7 | 2545421264546260 |
oct | 302224526435666 |
9 | 52241566838301 |
10 | 13351532510134 |
11 | 4288398034645 |
12 | 15b774928189a |
13 | 75b075bbc670 |
14 | 342309220b30 |
15 | 182486007974 |
hex | c24a55a3bb6 |
13351532510134 has 64 divisors (see below), whose sum is σ = 26102022944256. Its totient is φ = 4970633071104.
The previous prime is 13351532510119. The next prime is 13351532510153. The reversal of 13351532510134 is 43101523515331.
13351532510134 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×133515325101342 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13351532510093 and 13351532510102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 26241949 + ... + 26745895.
It is an arithmetic number, because the mean of its divisors is an integer number (407844108504).
Almost surely, 213351532510134 is an apocalyptic number.
13351532510134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13351532510134 is a deficient number, since it is larger than the sum of its proper divisors (12750490434122).
13351532510134 is a wasteful number, since it uses less digits than its factorization.
13351532510134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 512549.
The product of its (nonzero) digits is 81000, while the sum is 37.
The spelling of 13351532510134 in words is "thirteen trillion, three hundred fifty-one billion, five hundred thirty-two million, five hundred ten thousand, one hundred thirty-four".
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