Base | Representation |
---|---|
bin | 1100001001001100000111… |
… | …1100100000011111111111 |
3 | 1202021102212200121010010111 |
4 | 3002103001330200133333 |
5 | 3222224410112023130 |
6 | 44221455120050451 |
7 | 2545436211166441 |
oct | 302230174403777 |
9 | 52242780533114 |
10 | 13352012220415 |
11 | 42886138a3020 |
12 | 15b7861a63a27 |
13 | 75b1213bc4bb |
14 | 342352c14491 |
15 | 1824b31b402a |
hex | c24c1f207ff |
13352012220415 has 32 divisors (see below), whose sum is σ = 18402098077440. Its totient is φ = 9197896032000.
The previous prime is 13352012220329. The next prime is 13352012220433. The reversal of 13352012220415 is 51402221025331.
It is a happy number.
It is not a de Polignac number, because 13352012220415 - 213 = 13352012212223 is a prime.
It is a super-2 number, since 2×133520122204152 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5022427 + ... + 7206163.
It is an arithmetic number, because the mean of its divisors is an integer number (575065564920).
Almost surely, 213352012220415 is an apocalyptic number.
13352012220415 is a deficient number, since it is larger than the sum of its proper divisors (5050085857025).
13352012220415 is a wasteful number, since it uses less digits than its factorization.
13352012220415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2189623.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 13352012220415 its reverse (51402221025331), we get a palindrome (64754233245746).
The spelling of 13352012220415 in words is "thirteen trillion, three hundred fifty-two billion, twelve million, two hundred twenty thousand, four hundred fifteen".
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