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13352113154230 = 251576398470057
BaseRepresentation
bin1100001001001100011111…
…1101100010100010110110
31202021110010201112002021221
43002103013331202202312
53222230111431413410
644221513123300554
72545441545131224
oct302230775424266
952243121462257
1013352113154230
1142886658720a4
1215b788b81a75a
1375b13929c056
143423623a9b14
151824bbea04da
hexc24c7f628b6

13352113154230 has 16 divisors (see below), whose sum is σ = 24033958976160. Its totient is φ = 5340810750912.

The previous prime is 13352113154203. The next prime is 13352113154251. The reversal of 13352113154230 is 3245131125331.

13352113154230 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2658639 + ... + 5811418.

It is an arithmetic number, because the mean of its divisors is an integer number (1502122436010).

Almost surely, 213352113154230 is an apocalyptic number.

13352113154230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13352113154230 is a deficient number, since it is larger than the sum of its proper divisors (10681845821930).

13352113154230 is a wasteful number, since it uses less digits than its factorization.

13352113154230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8627703.

The product of its (nonzero) digits is 32400, while the sum is 34.

Adding to 13352113154230 its reverse (3245131125331), we get a palindrome (16597244279561).

The spelling of 13352113154230 in words is "thirteen trillion, three hundred fifty-two billion, one hundred thirteen million, one hundred fifty-four thousand, two hundred thirty".

Divisors: 1 2 5 10 157639 315278 788195 1576390 8470057 16940114 42350285 84700570 1335211315423 2670422630846 6676056577115 13352113154230