Base | Representation |
---|---|
bin | 1100001001001100011111… |
… | …1101100010100010110110 |
3 | 1202021110010201112002021221 |
4 | 3002103013331202202312 |
5 | 3222230111431413410 |
6 | 44221513123300554 |
7 | 2545441545131224 |
oct | 302230775424266 |
9 | 52243121462257 |
10 | 13352113154230 |
11 | 42886658720a4 |
12 | 15b788b81a75a |
13 | 75b13929c056 |
14 | 3423623a9b14 |
15 | 1824bbea04da |
hex | c24c7f628b6 |
13352113154230 has 16 divisors (see below), whose sum is σ = 24033958976160. Its totient is φ = 5340810750912.
The previous prime is 13352113154203. The next prime is 13352113154251. The reversal of 13352113154230 is 3245131125331.
13352113154230 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2658639 + ... + 5811418.
It is an arithmetic number, because the mean of its divisors is an integer number (1502122436010).
Almost surely, 213352113154230 is an apocalyptic number.
13352113154230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13352113154230 is a deficient number, since it is larger than the sum of its proper divisors (10681845821930).
13352113154230 is a wasteful number, since it uses less digits than its factorization.
13352113154230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8627703.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 13352113154230 its reverse (3245131125331), we get a palindrome (16597244279561).
The spelling of 13352113154230 in words is "thirteen trillion, three hundred fifty-two billion, one hundred thirteen million, one hundred fifty-four thousand, two hundred thirty".
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