Base | Representation |
---|---|
bin | 1100001001001100100010… |
… | …1011001100011111110110 |
3 | 1202021110011120001010202001 |
4 | 3002103020223030133312 |
5 | 3222230123012410200 |
6 | 44221514232005514 |
7 | 2545442051636254 |
oct | 302231053143766 |
9 | 52243146033661 |
10 | 13352125122550 |
11 | 42886715a7075 |
12 | 15b789383089a |
13 | 75b13b8cc7b6 |
14 | 342363c035d4 |
15 | 1824bd06676a |
hex | c24c8acc7f6 |
13352125122550 has 48 divisors (see below), whose sum is σ = 24871305290832. Its totient is φ = 5333034672000.
The previous prime is 13352125122493. The next prime is 13352125122563. The reversal of 13352125122550 is 5522152125331.
13352125122550 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 256494025 + ... + 256546075.
It is an arithmetic number, because the mean of its divisors is an integer number (518152193559).
Almost surely, 213352125122550 is an apocalyptic number.
13352125122550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13352125122550 is a deficient number, since it is larger than the sum of its proper divisors (11519180168282).
13352125122550 is a wasteful number, since it uses less digits than its factorization.
13352125122550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59473 (or 59468 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 37.
Adding to 13352125122550 its reverse (5522152125331), we get a palindrome (18874277247881).
The spelling of 13352125122550 in words is "thirteen trillion, three hundred fifty-two billion, one hundred twenty-five million, one hundred twenty-two thousand, five hundred fifty".
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