Base | Representation |
---|---|
bin | 111110001011010111… |
… | …1010111100111001101 |
3 | 110202122121210022202021 |
4 | 1330112233113213031 |
5 | 4141430012034123 |
6 | 141201334530141 |
7 | 12434613021022 |
oct | 1742657274715 |
9 | 422577708667 |
10 | 133525502413 |
11 | 5169a735296 |
12 | 21a65506951 |
13 | c78c3ccc34 |
14 | 66697c5549 |
15 | 371760bc5d |
hex | 1f16bd79cd |
133525502413 has 2 divisors, whose sum is σ = 133525502414. Its totient is φ = 133525502412.
The previous prime is 133525502359. The next prime is 133525502483. The reversal of 133525502413 is 314205525331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 103940470404 + 29585032009 = 322398^2 + 172003^2 .
It is a cyclic number.
It is not a de Polignac number, because 133525502413 - 233 = 124935567821 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133525502483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66762751206 + 66762751207.
It is an arithmetic number, because the mean of its divisors is an integer number (66762751207).
Almost surely, 2133525502413 is an apocalyptic number.
It is an amenable number.
133525502413 is a deficient number, since it is larger than the sum of its proper divisors (1).
133525502413 is an equidigital number, since it uses as much as digits as its factorization.
133525502413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 34.
The spelling of 133525502413 in words is "one hundred thirty-three billion, five hundred twenty-five million, five hundred two thousand, four hundred thirteen".
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