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13353040343117 is a prime number
BaseRepresentation
bin1100001001001111111100…
…1110011111000001001101
31202021112112100012011100002
43002103333032133001031
53222234011311434432
644222145124214045
72545503534116636
oct302237716370115
952245470164302
1013353040343117
114288aa1184902
1215b7aaa23a325
1375b2563c5027
1434240d5a288d
1518252359ce62
hexc24ff39f04d

13353040343117 has 2 divisors, whose sum is σ = 13353040343118. Its totient is φ = 13353040343116.

The previous prime is 13353040343077. The next prime is 13353040343219. The reversal of 13353040343117 is 71134304035331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10446250628356 + 2906789714761 = 3232066^2 + 1704931^2 .

It is an emirp because it is prime and its reverse (71134304035331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13353040343117 - 212 = 13353040339021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13353040343017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676520171558 + 6676520171559.

It is an arithmetic number, because the mean of its divisors is an integer number (6676520171559).

Almost surely, 213353040343117 is an apocalyptic number.

It is an amenable number.

13353040343117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13353040343117 is an equidigital number, since it uses as much as digits as its factorization.

13353040343117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 38.

Adding to 13353040343117 its reverse (71134304035331), we get a palindrome (84487344378448).

The spelling of 13353040343117 in words is "thirteen trillion, three hundred fifty-three billion, forty million, three hundred forty-three thousand, one hundred seventeen".