13353441353423 has 2 divisors, whose sum is σ = 13353441353424. Its totient is φ = 13353441353422.

The previous prime is 13353441353363. The next prime is 13353441353437. The reversal of 13353441353423 is 32435314435331.

13353441353423 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13353441353423 - 2¹⁰ = 13353441352399 is a prime.

It is a super-3 number, since 3×13353441353423³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13353441353443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676720676711 + 6676720676712.

It is an arithmetic number, because the mean of its divisors is an integer number (6676720676712).

Almost surely, 2^{13353441353423} is an apocalyptic number.

13353441353423 is a deficient number, since it is larger than the sum of its proper divisors (1).

13353441353423 is an equidigital number, since it uses as much as digits as its factorization.

13353441353423 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2332800, while the sum is 44.

Adding to 13353441353423 its reverse (32435314435331), we get a palindrome (45788755788754).

The spelling of 13353441353423 in words is "thirteen trillion, three hundred fifty-three billion, four hundred forty-one million, three hundred fifty-three thousand, four hundred twenty-three".