13354040051100 has 432 divisors, whose sum is σ = 48232546252800. Its totient is φ = 3027221683200.

The previous prime is 13354040050999. The next prime is 13354040051167. The reversal of 13354040051100 is 115004045331.

It is a happy number.

13354040051100 is a `hidden beast` number, since 1 + 3 + 3 + 540 + 4 + 0 + 0 + 5 + 110 + 0 = 666.

It is a super-3 number, since 3×13354040051100³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 392391085 + ... + 392425115.

Almost surely, 2^{13354040051100} is an apocalyptic number.

13354040051100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13354040051100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24116273126400).

13354040051100 is an abundant number, since it is smaller than the sum of its proper divisors (34878506201700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13354040051100 is a wasteful number, since it uses less digits than its factorization.

13354040051100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34570 (or 34560 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 27.

Adding to 13354040051100 its reverse (115004045331), we get a palindrome (13469044096431).

The spelling of 13354040051100 in words is "thirteen trillion, three hundred fifty-four billion, forty million, fifty-one thousand, one hundred".