Base | Representation |
---|---|
bin | 1111111010110… |
… | …11100001101001 |
3 | 100022021201222121 |
4 | 13331123201221 |
5 | 233141402131 |
6 | 21130151241 |
7 | 3211051141 |
oct | 775334151 |
9 | 308251877 |
10 | 133544041 |
11 | 69422684 |
12 | 38882521 |
13 | 21889957 |
14 | 13a43921 |
15 | bacd911 |
hex | 7f5b869 |
133544041 has 2 divisors, whose sum is σ = 133544042. Its totient is φ = 133544040.
The previous prime is 133544039. The next prime is 133544053. The reversal of 133544041 is 140445331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 75342400 + 58201641 = 8680^2 + 7629^2 .
It is a cyclic number.
It is not a de Polignac number, because 133544041 - 21 = 133544039 is a prime.
Together with 133544039, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 133543997 and 133544015.
It is not a weakly prime, because it can be changed into another prime (133542041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66772020 + 66772021.
It is an arithmetic number, because the mean of its divisors is an integer number (66772021).
Almost surely, 2133544041 is an apocalyptic number.
It is an amenable number.
133544041 is a deficient number, since it is larger than the sum of its proper divisors (1).
133544041 is an equidigital number, since it uses as much as digits as its factorization.
133544041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 25.
The square root of 133544041 is about 11556.1256915975. The cubic root of 133544041 is about 511.1419254141.
Adding to 133544041 its reverse (140445331), we get a palindrome (273989372).
The spelling of 133544041 in words is "one hundred thirty-three million, five hundred forty-four thousand, forty-one".
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