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13355003222999 is a prime number
BaseRepresentation
bin1100001001010111010000…
…1110010001101111010111
31202021201121010200210022222
43002111310032101233113
53222302021311113444
644223112003412555
72545603300246544
oct302256416215727
952251533623288
1013355003222999
114289909178589
1215b835768415b
1375b4a9c73609
14342558157bcb
151825daa7beee
hexc2574391bd7

13355003222999 has 2 divisors, whose sum is σ = 13355003223000. Its totient is φ = 13355003222998.

The previous prime is 13355003222923. The next prime is 13355003223047. The reversal of 13355003222999 is 99922230055331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13355003222999 is a prime.

It is a super-4 number, since 4×133550032229994 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 13355003222999.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13355003822999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6677501611499 + 6677501611500.

It is an arithmetic number, because the mean of its divisors is an integer number (6677501611500).

Almost surely, 213355003222999 is an apocalyptic number.

13355003222999 is a deficient number, since it is larger than the sum of its proper divisors (1).

13355003222999 is an equidigital number, since it uses as much as digits as its factorization.

13355003222999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3936600, while the sum is 53.

The spelling of 13355003222999 in words is "thirteen trillion, three hundred fifty-five billion, three million, two hundred twenty-two thousand, nine hundred ninety-nine".