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133554513224543 is a prime number
BaseRepresentation
bin11110010111011110010101…
…010100011010001101011111
3122111212200112122202000020212
4132113132111110122031133
5120001124120341141133
61152014032452203035
740062665224461065
oct3627362524321537
9574780478660225
10133554513224543
1139611172a57894
1212b8b91430947b
13596a1a1029828
1424da104198035
1510690d5617148
hex79779551a35f

133554513224543 has 2 divisors, whose sum is σ = 133554513224544. Its totient is φ = 133554513224542.

The previous prime is 133554513224519. The next prime is 133554513224567. The reversal of 133554513224543 is 345422315455331.

It is a balanced prime because it is at equal distance from previous prime (133554513224519) and next prime (133554513224567).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133554513224543 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133554513224491 and 133554513224500.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133554513224593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66777256612271 + 66777256612272.

It is an arithmetic number, because the mean of its divisors is an integer number (66777256612272).

Almost surely, 2133554513224543 is an apocalyptic number.

133554513224543 is a deficient number, since it is larger than the sum of its proper divisors (1).

133554513224543 is an equidigital number, since it uses as much as digits as its factorization.

133554513224543 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12960000, while the sum is 50.

Adding to 133554513224543 its reverse (345422315455331), we get a palindrome (478976828679874).

The spelling of 133554513224543 in words is "one hundred thirty-three trillion, five hundred fifty-four billion, five hundred thirteen million, two hundred twenty-four thousand, five hundred forty-three".