Base | Representation |
---|---|
bin | 1100001001101111010101… |
… | …1011111110101111001100 |
3 | 1202022100021112122002011022 |
4 | 3002123311123332233030 |
5 | 3222403240301341330 |
6 | 44230101152213312 |
7 | 2546222404311422 |
oct | 302336533765714 |
9 | 52270245562138 |
10 | 13361466043340 |
11 | 4291625281118 |
12 | 15b965bb3a238 |
13 | 75bc99ba756c |
14 | 3429ac601112 |
15 | 182868136ae5 |
hex | c26f56febcc |
13361466043340 has 24 divisors (see below), whose sum is σ = 28519063590192. Its totient is φ = 5256970246080.
The previous prime is 13361466043337. The next prime is 13361466043369. The reversal of 13361466043340 is 4334066416331.
It is a junction number, because it is equal to n+sod(n) for n = 13361466043291 and 13361466043300.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5476009454 + ... + 5476011893.
It is an arithmetic number, because the mean of its divisors is an integer number (1188294316258).
Almost surely, 213361466043340 is an apocalyptic number.
13361466043340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13361466043340 is an abundant number, since it is smaller than the sum of its proper divisors (15157597546852).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13361466043340 is a wasteful number, since it uses less digits than its factorization.
13361466043340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10952021417 (or 10952021415 counting only the distinct ones).
The product of its (nonzero) digits is 1119744, while the sum is 44.
The spelling of 13361466043340 in words is "thirteen trillion, three hundred sixty-one billion, four hundred sixty-six million, forty-three thousand, three hundred forty".
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