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133650440381 is a prime number
BaseRepresentation
bin111110001111000101…
…1111110000010111101
3110202222022212211102102
41330132023332002331
54142204003043011
6141222000434445
712440660666453
oct1743613760275
9422868784372
10133650440381
115175420a007
1221a9b318a25
13c7ac265623
14667c2289d3
15372358a73b
hex1f1e2fe0bd

133650440381 has 2 divisors, whose sum is σ = 133650440382. Its totient is φ = 133650440380.

The previous prime is 133650440311. The next prime is 133650440389. The reversal of 133650440381 is 183044056331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84381535225 + 49268905156 = 290485^2 + 221966^2 .

It is an emirp because it is prime and its reverse (183044056331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133650440381 - 214 = 133650423997 is a prime.

It is a super-2 number, since 2×1336504403812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133650440389) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66825220190 + 66825220191.

It is an arithmetic number, because the mean of its divisors is an integer number (66825220191).

Almost surely, 2133650440381 is an apocalyptic number.

It is an amenable number.

133650440381 is a deficient number, since it is larger than the sum of its proper divisors (1).

133650440381 is an equidigital number, since it uses as much as digits as its factorization.

133650440381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 38.

The spelling of 133650440381 in words is "one hundred thirty-three billion, six hundred fifty million, four hundred forty thousand, three hundred eighty-one".