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133650941 is a prime number
BaseRepresentation
bin1111111011101…
…01100111111101
3100022111011121212
413331311213331
5233203312231
621132334205
73212004614
oct775654775
9308434555
10133650941
1169495a26
1238914365
13218c64c8
1413a7087b
15bb0042b
hex7f759fd

133650941 has 2 divisors, whose sum is σ = 133650942. Its totient is φ = 133650940.

The previous prime is 133650931. The next prime is 133650949. The reversal of 133650941 is 149056331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133494916 + 156025 = 11554^2 + 395^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133650941 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 133650898 and 133650907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133650949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66825470 + 66825471.

It is an arithmetic number, because the mean of its divisors is an integer number (66825471).

Almost surely, 2133650941 is an apocalyptic number.

It is an amenable number.

133650941 is a deficient number, since it is larger than the sum of its proper divisors (1).

133650941 is an equidigital number, since it uses as much as digits as its factorization.

133650941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 32.

The square root of 133650941 is about 11560.7500189218. The cubic root of 133650941 is about 511.2782761843.

The spelling of 133650941 in words is "one hundred thirty-three million, six hundred fifty thousand, nine hundred forty-one".