Base | Representation |
---|---|
bin | 11110011001000011011101… |
… | …111101100110100000001111 |
3 | 122112021001211200111221110022 |
4 | 132121003131331212200033 |
5 | 120004414020134233001 |
6 | 1152135552215532355 |
7 | 40103561242313312 |
oct | 3631033575464017 |
9 | 575231750457408 |
10 | 133663106164751 |
11 | 39653228927069 |
12 | 12ba897b98a0bb |
13 | 59774b8b75777 |
14 | 250148654c979 |
15 | 106bd3de2311b |
hex | 7990ddf6680f |
133663106164751 has 2 divisors, whose sum is σ = 133663106164752. Its totient is φ = 133663106164750.
The previous prime is 133663106164613. The next prime is 133663106164781. The reversal of 133663106164751 is 157461601366331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133663106164751 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133663106164693 and 133663106164702.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133663106164781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66831553082375 + 66831553082376.
It is an arithmetic number, because the mean of its divisors is an integer number (66831553082376).
Almost surely, 2133663106164751 is an apocalyptic number.
133663106164751 is a deficient number, since it is larger than the sum of its proper divisors (1).
133663106164751 is an equidigital number, since it uses as much as digits as its factorization.
133663106164751 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4898880, while the sum is 53.
The spelling of 133663106164751 in words is "one hundred thirty-three trillion, six hundred sixty-three billion, one hundred six million, one hundred sixty-four thousand, seven hundred fifty-one".
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