Base | Representation |
---|---|
bin | 11110011001000011110001… |
… | …100101100010011100010111 |
3 | 122112021002200122000212122211 |
4 | 132121003301211202130113 |
5 | 120004420203430312413 |
6 | 1152140045020334251 |
7 | 40103602350630565 |
oct | 3631036145423427 |
9 | 575232618025584 |
10 | 133663435400983 |
11 | 3965338775a124 |
12 | 12ba8a520a4387 |
13 | 597753c13b9c7 |
14 | 25014b8172a35 |
15 | 106bd5cca983d |
hex | 7990f1962717 |
133663435400983 has 2 divisors, whose sum is σ = 133663435400984. Its totient is φ = 133663435400982.
The previous prime is 133663435400867. The next prime is 133663435401007. The reversal of 133663435400983 is 389004534366331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133663435400983 - 29 = 133663435400471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133663435400083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66831717700491 + 66831717700492.
It is an arithmetic number, because the mean of its divisors is an integer number (66831717700492).
Almost surely, 2133663435400983 is an apocalyptic number.
133663435400983 is a deficient number, since it is larger than the sum of its proper divisors (1).
133663435400983 is an equidigital number, since it uses as much as digits as its factorization.
133663435400983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50388480, while the sum is 58.
The spelling of 133663435400983 in words is "one hundred thirty-three trillion, six hundred sixty-three billion, four hundred thirty-five million, four hundred thousand, nine hundred eighty-three".
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