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133726423419077 is a prime number
BaseRepresentation
bin11110011001111110011011…
…111101110000100011000101
3122112111010021101002201122212
4132121332123331300203011
5120011433203343402302
61152225023144233205
740111262302145366
oct3631763375604305
9575433241081585
10133726423419077
113967806a863425
1212bb90b076b805
135980469946728
1425045717cdb6d
15106d7e79d6052
hex799f9bf708c5

133726423419077 has 2 divisors, whose sum is σ = 133726423419078. Its totient is φ = 133726423419076.

The previous prime is 133726423419059. The next prime is 133726423419079. The reversal of 133726423419077 is 770914324627331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133637160503716 + 89262915361 = 11560154^2 + 298769^2 .

It is a cyclic number.

It is not a de Polignac number, because 133726423419077 - 216 = 133726423353541 is a prime.

Together with 133726423419079, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133726423419079) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66863211709538 + 66863211709539.

It is an arithmetic number, because the mean of its divisors is an integer number (66863211709539).

Almost surely, 2133726423419077 is an apocalyptic number.

It is an amenable number.

133726423419077 is a deficient number, since it is larger than the sum of its proper divisors (1).

133726423419077 is an equidigital number, since it uses as much as digits as its factorization.

133726423419077 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32006016, while the sum is 59.

The spelling of 133726423419077 in words is "one hundred thirty-three trillion, seven hundred twenty-six billion, four hundred twenty-three million, four hundred nineteen thousand, seventy-seven".