Base | Representation |
---|---|
bin | 111110010001100000… |
… | …0011011110000000111 |
3 | 110210011222001001021021 |
4 | 1330203000123300013 |
5 | 4142340203134112 |
6 | 141234005532011 |
7 | 12442662213013 |
oct | 1744300336007 |
9 | 423158031237 |
10 | 133731302407 |
11 | 5179591992a |
12 | 21b02414007 |
13 | c7c2c38191 |
14 | 6688c77543 |
15 | 372a70e907 |
hex | 1f2301bc07 |
133731302407 has 2 divisors, whose sum is σ = 133731302408. Its totient is φ = 133731302406.
The previous prime is 133731302399. The next prime is 133731302423. The reversal of 133731302407 is 704203137331.
It is a weak prime.
It is an emirp because it is prime and its reverse (704203137331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133731302407 - 23 = 133731302399 is a prime.
It is a super-2 number, since 2×1337313024072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133731302207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66865651203 + 66865651204.
It is an arithmetic number, because the mean of its divisors is an integer number (66865651204).
Almost surely, 2133731302407 is an apocalyptic number.
133731302407 is a deficient number, since it is larger than the sum of its proper divisors (1).
133731302407 is an equidigital number, since it uses as much as digits as its factorization.
133731302407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31752, while the sum is 34.
Adding to 133731302407 its reverse (704203137331), we get a palindrome (837934439738).
The spelling of 133731302407 in words is "one hundred thirty-three billion, seven hundred thirty-one million, three hundred two thousand, four hundred seven".
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